Two inductors of inductance 4 II and 8 II are arrange in series and a current of 10 A is passed through them. What is the energy stored in them?

Eduoladipupo

7 years ago

Series connection of inductor is nt a fraction dat is d 1 for parallel

SammyKush011

5 years ago

E = 1/2LI² = 1/2×12×100 = 600J

Chukwummesomachukwu

1 year ago

Good job keep it up

SammyKush011

5 years ago

series arrangement of inductors gives an effective inductance which is the algebraic sum of the individual inductors

L = 4+ 8 = 12H
E = LI² = 12×10² = 12×100 = 1200J