A machine is used to lift a load of 20 N through a height of 10 m. if the efficiency of the machine is 40%, how much work is done?

De sage

1 year ago

Efficiency= Distance moved by the load/distance moved by the effort × 100/1

E= DL/DE×100/1
E= 40
DL= 20×10= 200
DE=?

40= 200/DE×100
40DE= 20000
divide both sides by 40
DE= 20000/40
DE= 500

Anthony A.V

10 years ago

I made a Mistake pls...it ought 2 b 40%=Mgh/workdone by d machine =40/100 = 20x10/workdone by d machine...i'm sorry if i misled u

Myschool Amos

10 years ago

Thanks for your contributions,necessary changes have been made.

mgb4real

12 years ago

I doubt if you guys got what the question required.

mgb4real

12 years ago

We already know the work output which is the useful workdone. what we are asked to find is actually the work input which is 500J

SCHOLARSTIC

10 years ago

The answers is 500j

Anthony A.V

10 years ago

D working n ansa provided is nt correct i.e it is supposed 2 b 40/100= 20X10X10/work done by d machine...

theovicg

11 years ago

YO U AREAOL