The fundamental frequency of a plucked wire under a tension of 400N is 250Hz. When the frequency is changed to 500 Hz at constant length, the tension is

dice419

1 year ago

f=(sqrtT)k
f1/(sqrtT1) = f2/(sqrtT2)
sqrtT2=(sqrt400 ×500)/250
sqrtT2 = 40
square both sides
T2 = 40²
T2 =1600N.

darkypearl

12 years ago

aw com 500/250* 400 gave 2*20 =40??

its meant 2b 800 na

NwobaKelechy

9 years ago

In Which Topic Can I Read This 'Tension &Force' In Physics

Ugbo jerry

11 years ago

use inverse variation method to solve it,,u will get d answer first find d fornula that connects it den get d value of d constant n use the relationship to find d value of T.d answer is 1600

Dandiyn28

1 year ago

the answer is correct factually 👍

J.julian

2 months ago

?

Mira_231

2 years ago

The correct answer is 1,600N