The ground state energy for the hydrogen atom is 5.44 x 10\(^{-19}\)J. If an electron drops from zero energy to the ground state, calculate the frequency of the emitted radiation. [h = 6.6 x 10\(^{-34}\) Js]

Refhord

3 years ago

☹️☹️ but in jamb is from A to D

Anela

1 year ago

∆E = hf
E=5.44×10-¹⁹
h= 6.6×10-³⁴

5.44x10-¹⁹ = 6.6x10-³⁴ f
DBS BY 6.6×10-³⁴
f=5.44/6.6 x 10-¹⁹+³⁴
= 0.8242x10¹⁵
= 8.24x10¹⁴(ANS)

U CAN DO A LITTLE RESEARCH ON ADDITION AND SUBTRACTION OF STANDARD FORM TO UNDERSTAND HOW I SOLVED THE POWERS🤷🏻or whatever it's called.😁

Patience_Sunday

1 year ago

I don't understand the calculation.