An engine of a car of power 80 kW moves on a rough road with a velocity of 32 m\(s^-1\). The forces required to bring it to rest is
Power = force x velocity
=> 80,000 = F x 32
F = \(\frac{80000}{32}\)
= 2500N
= 2.50 x \(10^3\)N
There is an explanation video available below.
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