If ∆x is the uncertainty in the measurement of the position of a particle along the x-axis and ∆Pa is the uncertainty in the measurement of the linear momentum along the x-axis, then the uncertainty principle relation is given as

a

∆x ∆Px ≥ h

b

∆x ∆Px = 0

c

∆x ∆Px < h

d

∆x ∆Px = ∞

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The correct answer is:

A. ∆x ∆Px ≥ h

But there's a small refinement needed — according to Heisenberg's Uncertainty Principle, the more precise form of the inequality is:

Δ
𝑥

Δ
𝑃
𝑥


4
𝜋
Δx⋅ΔP
x



h


Or, using the reduced Planck's constant (

=

2
𝜋
ℏ=

h

):

Δ
𝑥

Δ
𝑃
𝑥


2
Δx⋅ΔP
x


2



So technically, answer A is a simplified version (using just

h), but it's the best choice among the options provided.

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