If ∆x is the uncertainty in the measurement of the position of a particle along the x-axis and ∆Pa is the uncertainty in the measurement of the linear momentum along the x-axis, then the uncertainty principle relation is given as
a
∆x ∆Px ≥ h
b
∆x ∆Px = 0
c
∆x ∆Px < h
d
∆x ∆Px = ∞
Explanation
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Khadijahbintkhuwalid
1 year ago
The correct answer is:
A. ∆x ∆Px ≥ h
But there's a small refinement needed — according to Heisenberg's Uncertainty Principle, the more precise form of the inequality is:
Δ
𝑥
⋅
Δ
𝑃
𝑥
≥
ℎ
4
𝜋
Δx⋅ΔP
x
≥
4π
h
Or, using the reduced Planck's constant (
ℏ
=
ℎ
2
𝜋
ℏ=
2π
h
):
Δ
𝑥
⋅
Δ
𝑃
𝑥
≥
ℏ
2
Δx⋅ΔP
x
≥
2
ℏ
So technically, answer A is a simplified version (using just
ℎ
h), but it's the best choice among the options provided.

