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The density of a certain oil on frying becomes 0.4 kgm\(^{-3}\) with the volume of...

Physics
JAMB 2010

The density of a certain oil on frying becomes 0.4 kgm\(^{-3}\) with the volume of 20m\(^{3}\). what will be its initial volume when its initial density is 0.8 kgm\(^{-3}\) assuming no loss of oil due to spillage?

  • A. 12m3
  • B. 10m3
  • C. 8m3
  • D. 5m3
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Correct Answer: Option B
Explanation

Density (D) = \(\frac{mass}{volume}\)

\(\therefore Mass = Density \times volume\)

= \(0.4 \times 20 = 8kg\)

The initial volume = \(\frac{Mass}{\text{Initial density}}\)

= \(\frac{8}{0.8} = 10m^{3}\)

There is an explanation video available below.


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Explanation Video

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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995