In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?

Bettyjoan

6 years ago

I think the formula is; pressure=force/area
P=100pa
A=3m^2
F=?
100=f/3
f=3*100
f=300N

dice419

1 year ago

1pa is 1N of force applied over a area of 1m²
so 100pa will be 100N of force applied over 1m².

so
f1/a1=f2/a2
100N/1m²=f2/3m²
f2 =300N

kankan esther

11 years ago

Hmmmmmmmmm moving forward

Odinakaprosper

3 months ago

correct

Yasminmama

3 years ago

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