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\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \) In...

Physics
JAMB 2005

\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \)

In the reaction above, X is

  • A. electron
  • B. proton
  • C. neutrino
  • D. neutron
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Correct Answer: Option D
Explanation

\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2^1_0X \)
In the reaction above, balancing the left with the right shows that X is a neutron

There is an explanation video available below.


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Explanation Video

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