In the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the acceleration of the system in motion is

a
5 ms-2
b
15 ms-2
c
3 ms-2
d
9 ms-2
Explanation
Correct Option
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Discussions (8)

De sage
1 year ago
mass
M2/M1
M2=6kg
m1=3kg
6/3=2kg
F=UR
F= ?
U=0.5
R=mg(2×10)
therefore
F= 0.5×20=10N
but we are looking for acceleration
F=ma
F=10N
m=2kg
a= ?
10=2a
a=10/2
a=5m/s²

Osheke
1 year ago
i might have used the wrong formula to get the correct answer..
since 6kg happens to be the driving mass/weight.
m= 6kg
W or N=60N
Frictional force= Ma
UN=Ma
0.5(60)=6a
30= 6a
a= 30/6
a= 5m/s²



