In the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the acceleration of the system in motion is

a

5 ms-2

b

15 ms-2

c

3 ms-2

d

9 ms-2

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Explanation

Correct Option
a

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Discussions (8)

De sage
1 year ago

mass
M2/M1
M2=6kg
m1=3kg
6/3=2kg

F=UR
F= ?
U=0.5
R=mg(2×10)
therefore
F= 0.5×20=10N

but we are looking for acceleration
F=ma
F=10N
m=2kg
a= ?
10=2a
a=10/2
a=5m/s²

Osheke
1 year ago

i might have used the wrong formula to get the correct answer..
since 6kg happens to be the driving mass/weight.
m= 6kg
W or N=60N

Frictional force= Ma
UN=Ma
0.5(60)=6a
30= 6a
a= 30/6
a= 5m/s²

Chrisplendour
2 years ago
Image

MaxMalone
1 year ago

can also use
T-Ur=ma
R-T=ma

u will still get Same answer

Bougie
4 years ago

I don't understand. Any explanation please?

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