An object is placed 5 cm from the pole of a concave mirror. if the focal length of the mirror is 10 cm. what is the image distance?

Rooseveltasogwa

4 years ago

This is me studying jamb cbt a day before the exam ..... wish i had more time to gain more , hope and God are those that i hang on now. The past questions ive been doing are nothing like this cbt
i know by the grace of God ill come back to this site not for the purpose of retaking the exam but to comment that i need help on some projects in my university

De sage

1 year ago

To find the image distance, we can use the mirror equation:

1/f = 1/do + 1/di

Given:
f = 10 cm
do = 5 cm

1/10 = 1/5 + 1/di
1/di = 1/10 - 1/5
1/di = 1/10 - 2/10
1/di = -1/10

di = -10 cm

Since the image distance is negative, the image is in front of the mirror and virtual.

However, considering the object is between the focal point and the mirror (5 cm < 10 cm), the correct interpretation is:

The correct answer is:

A) 10 cm in front of the mirror

gbagbendasusan

2 years ago

Amen hope too

De sage

1 year ago

sorry 10 cm behind the mirror because it is negative and virtual

chikodigift

1 year ago

The answer is a
Concave lens is negative while convex lens is positive
So the solving is
U(object distance)=-5
F(focal length)=-10
1/-10=1/v+(1/-5)
1/-10+1/5=1/v
v=10
If the image distance is positive is at the front of the mirror
If the image distance is negative is behind the mirror
So the answer is 10xm in front of the mirror

Anela

1 year ago

1/f = 1/V + 1/U
1/f= 1/10
1/U= 1/5
1/V = ?

1/10 = 1/5 + 1/V
LCM OF 5&V is 5V

1/10 = V+5/5V
CROSS MULTIPLY ✖️

5V = 10(V+5)
5V = 10V + 50
COLLECT LIKE TERMS
=5V-10V = 50
= -5V = 50
DBS BY -5

V= 50/-5
= -10(ANS)

It's behind the mirror since it's -ve