Physics
JAMB 2009
If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?
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A.
6.0 x 10-2J
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B.
7.6 x 10-2J
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C.
1.8 x 10-2J
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D.
6.6 x 10-2J
Correct Answer: Option A
Explanation
Work done on a stretched cord
= Average force x extension
= \(\frac{1 \times 10 \times 0.012}{2}\)
= 6.0 x 10\(^{-2}\)J
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