If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?

umeudu Francis

11 years ago

no. 45)

p= average force *extension

10/2 *( 12/100)

5 * 1.2 *10^2

ans=6.0 *10^-2

AndohOmotayo

3 years ago

please try to explain this questions more deeply ,i don't know if you understand me sha

Davidmayor24

1 year ago

There is a typographical error in the question. It should be weight 10N not mass 10N.

TonbraGuwor580

3 years ago

thnks

gbagbendasusan

2 years ago

thanks Christopher

Smartdaddy69

2 years ago

which one is mass of 10N???

egesiprecious

2 months ago

the formula is ½Fe
it's supposed to be weight not mass
So,½x10x0.012(after conversion)
5x0.012=0.06 or 6.0x10-²
how you understand

Michaelaudrey

11 months ago

Please I don't understand the solving of the question

Sensei

2 months ago

i object