If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in a minute, what is the total power expended?
[g = 10 ms2]
Power = \(\frac{work done}{time taken}\)
where 1 min = 60s
= \(\frac{mgh}{t}\)
= \(\frac{750 \times 10 \times 90}{60}\)
= 11250w or 11.25kw
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}