If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in a minute, what is the total power expended?
[g = 10 m\s\(^2\)]
Power = \(\frac{work done}{time taken}\)
where 1 min = 60s
= \(\frac{mgh}{t}\)
= \(\frac{750 \times 10 \times 90}{60}\)
= 11250w or 11.25kw
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