Caesium has a work function of 3 x 10\(^{-19}\)J. The maximum energy of liberated electrons when it is illuminated by light of frequency 6.7 x 10\(^{14}\)

HZ is?  [h = 6.6 x 10\(^{-34}\)Js]

a

1.42 x 10-19J

b

3.00 x 10-19J

c

4.42 x 1010-19J

d

7.42 x 10-19J

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Correct Option
a

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Discussions (6)

leoflex
10 years ago

this exam actually made sense ... keep up the good work

Wawaaaaaaaaaaaqa
2 years ago

maximum energy = kinetic energy
work function + kinetic energy = hf

Shanice97
3 years ago

the values are not really clear.

ImmaVynde
1 year ago

I no really understand

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