An object of heights 5 cm is placed at 20 cm from a concave mirror of focal length 10 cm. the image height is?
20 cm
15 cm
10 cm
5 cm
Explanation
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Discussions (15)
Formula= M = v-f/f
5= 20-10/10 = You cross multiply
5×10= 50
20- 10=10
Therefore 50/10= 5cm verified ✅😎
1/V + 1/U =1/F
1/V +1/20=1/10
1/V=1/20
V=20
m=image distance/object distance=image height/object height
X/5=20/20
X=5*1
X=5cm
HMPH 🥱🥱
. Done and dusted . 400 here I come 
smiles..
you don't even need much solvings though
since the focal length is 10cm and the object was placed at 20cm it means it was placed at 2f(center of curvature)
now at 2f image formed is
Real, inverted and same size as object which means that magnification will be m = 1
m = Image height/5
image height= 1×5 = 5🥱
you can still sopve with the conventional method if u feel its better
is everyone going to ignore the fact that they question is asking for image height not magnification
should be 20
