A piece of iron weights 250 N in air and 200 N in a liquid...

Physics

JAMB 2007

A piece of iron weights 250 N in air and 200 N in a liquid of density 1000 kgm-3. the volume of the iron is?

A. 5.0 x 10^-3 m^-3
B. 4.5 x 10^-3 m^-3
C. 2.5 x 10^-3 m^-3
D. 2.0 x 10^-3 m^-3

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Correct Answer: Option A

Explanation

Wt in the air = 250N
wt. in the liquid = 200N
loss in wt. in the liquid = 250 - 200 = 50N
∴ mass of liquid displaced = 50N → 5kg
∴If the density of the liquid is 1000kgm-3
then the volume of the liquid = (M)/D = V = (5kg)/1000 = 0.005 → 5.0 X \(10^{-3}\)\(m^3\)

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