A reservoir 500 m deep is filled with a fluid of density 850 kgm-3. If the atmospheric pressure is 1.05 x 105 Nm-2, the pressure at the bottom of the reservoir is.
[g = 10ms-2]
In general, pressure varies with depth in the relation p = \(\rho\)gh
= 850 x 10 x 500
= 4250000
= 4.25 x 10\(^6\) Nm\(^{-2}\)
Therefore, Total pressure = 1.05 x 10\(^5\) + 4.25 x 10\(^6\) = 4.36 x 10\(^6\) Nm\(^{-2}\)
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}