The wavelength of the first overtone of a note in a closed pipe of length 33 cm is?
In a closed tube, the fundamental note occurs when the length of the tube l = \(\frac{λ}{4}\),
the first overtone occurs when the length of the tube l = \(\frac{3 \lambda}{4}\)
λ = \(\frac{4l}{3}\) = \(\frac{ 4 \times 33}{3}\) = 44 cm
There is an explanation video available below.
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