An object placed 10cm from a concave mirror of focal length 5cm would have its image
at the centre of convature
at the radius of curvature
at infinity
10 cm from the focus
Explanation
Video Explanation
Post your Contribution
Discussions (15)

1/F = 1/V + 1/U
1/5 = 1/V + 1/10
V = 10
but M = V/U
M = 10/10
M = 1
N/B: The magnification of the image formed by a concave mirror is 1, if the image is formed at the CENTER OF CURVATURE.
thus from the calculation above, the image is formed at the centre of curvature,.


Recllect from your cases of images formed in a concave mirror, the centre of curvature is twice the focal length.
Therefore, option A is correct.
The image is formed at the centre of curverture. Imagine a circle the radius is just a distance(in dis case the distance BTW the pole and the centre of curvature) but the centre is a point(wic we use wen locating image formed)

It should be B na since image distance is 10 we know that radius of curvature is 2times focal length which will give us 10 I go with b we can't just just assume from distance from pole to centre of curvature is 10









