If the radius of the Earth is 6.4 x 10\(^6\)m, the escape velocity of a satellite from the Earth is?
[g = 10 ms\(^-2\)]
V = √2GM/R.
=√[2 x 6.67 x 10\(^{-11}\) x 6.0 x 10\(^24\)] / 6.4 x 10\(^6\)
= √12.506 x 10\(^7\)
= 11,183.13
OR
V =√2gR
V=√[2 * 10 * 6.4 x 10\(^6\)]
V = √128,000,000
11,313.708
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}