The resistance of a piece of wire of length 20m has crossed-sectional area 8 x 10\(^{-6}\)m\(^2\)is?
[Resistivity of the wire = 4 x 10\(^{-7}\) Ω m]

Ayomi424

3 years ago

Resistance = Resistivity * length/Cross sectional area
R=4*10^-7 * 20/ 8*10^-6
R=8*10^-6/8*10^-6
R=1.0 ohms

brigelina

7 years ago

my school pls correct the question, the area is supposed to be raised to power (-6) not just six, as it is in your explanations.

Ibraahiim

1 year ago

not belonging to elasticity

solgade

1 year ago

R = pL/A
==>[4x10`-7 x 20] ÷ 8x10`-6

I.usman

3 years ago

My score is not compatibility