A proton moving with a speed of 1.0 x 10\(^6\)ms\(^{-1}\) through a magnetic field of 1.0T experiences a magnetic force of magnitude 8.0 x 10\(^{-14}\) N. The angle between the proton's velocity and the field is 

[1.6 x 10\(^{-19}\)C]

a

60°

b

90°

c

30°

d

45°

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Explanation

Correct Option
c

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Discussions (9)

deebsy
10 years ago

q is a constant 1.6x10^-19

Toclay
5 years ago

Go to page 432 in new school physics,u would see that q is constant as 1.6×10'-19

Sensei
2 months ago

Very correct

Craig Duffy
9 years ago

it doesn't mean...it shud HV been made known. Jxt like acceleration due to gravity(g).

Johnbinary
1 year ago

but jamb calc does not have inverse of sin even sin

Cand58c25c
1 year ago

my school please where did you see that constant value of yours to be q
in magnetic field q is always eletric charge and not constant and in flux density which is blv no q in it i wonder whete you got your constant please someone should help oo

J10kay
10 years ago

The question is wrongly composed:

The value of q is not given in the question. Please effect changes

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