A body of mass 4kg is acted on by a constant force of 12N for 3 seconds. The kinetic energy gained by the body at the end of the time is

Youngex

13 years ago

Alxo using newton 2nd law of momentum i.e F=m(v-u)/t...u=0

therefor F=mv/t

then v=Ft/m

subtitutin d values

v=12 x 3/4= 9m/s



nw, usin K.E=1/2MV2

we have 1x4x9x9/2 =162J.

DominicAfam

1 year ago

F=12N
t=3
m=4
V=?😭

F=ma
12=4a
a=12/4
a=3

V=u+at
V=0+(3×3)
V=0+9
V=9

K.E=1/2mv²
K.E=0.5×4×9²
K.E=162J 😂

✌️

kelvinityxy

2 years ago

I don't understand