In the diagram above, the ratio of he electric power dissipated in the 6Ω and the 3Ω resistor respectively is

molosfaith

7 years ago

simply use this:
P=V^2/R
for R= 6
12^2/6=144/6
R=24
for r = 3
12^2/3=144/3
r=48
R/r = 24/48
R:r= 1:2

Obehs

6 years ago

wrong answer. it should be 2:1
check your explanation very well

leonard001

2 years ago

let's clear this??

only those how have read on this would be able to relate, the mistake most of us are making is calculating the total resistance first before finding the power loss, nooooo



this is a parallel connection, remember that in a parallel connection the potential difference is the same but the current is not!!!! so you're to calculate like this i=12/6 to get current glowing in resistor 6

and for resistor 3 you to also do the same I=12/3
before solving for the power

nickki

11 years ago

exactly