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 The binding energy of helium \(^4 _2\) He is  [atomic mass of proton = 1.00783U,...

Physics
JAMB 2004

 The binding energy of helium \(^4 _2\) He is  [atomic mass of proton = 1.00783U, atomic mass of neutron = 1.00867U]

  • A. 4.033U
  • B. 2.017U
  • C. 0.033U
  • D. 0.330U
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Correct Answer: Option C
Explanation

The binding energy of a nucleus is the work done or energy needed to separate the nucleons (protons and neutrons) apart. Again, experiment shows that the total mass of all individual nucleons is greater than that of the nucleus in which they are together. This difference in mass is the measure of the binding energy of the particular nucleus.

For helium\(^4_2\)He

It has 4 nucleons, 2 protons and 2 neutrons
2:H = 2 x 1.00783 = 2.01566
2:n = 2 x 1.00867 = 2.01734
∴ 2:H + 2:n = 4.03300u
But the helium nucleus has a mass of 4.00260u
∴ Binding energy = difference between nucleons and nucleus
= 4.03300U - 4.00260U = 0.03040U

There is an explanation video available below.


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Explanation Video

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