A radioisotope has a decay constant of 10\(^{-7}\)s\(^{-1}\). The average life of the radioisotope is

chididarls

1 year ago

So everyone here is wrong, because decay constant =0.693/half life(T1/2), and average life(which isnt the same as half life) is given as Half life/0.693(ln2)

Also, as a shortcut, you could just do avg life=1/decay constant.

or When you relate the two equations with half life(which i dont have the strenght to do), you get:
option A. 1x10^7

Im quite sure about this one, myschool please correct.

cruz4handel

2 years ago

the answer is 6.93×10⁶

Abn124

1 year ago

the correct Option is a.
average life = 1/decay constant

ZOOMLORDchibuzor

5 years ago

0.693 ×10^7
=6930000

SammyKush011

6 years ago

no options for the correct answer either,
K = 0.693/t1/2
t1/2=0.693/K
t1/2 = 6.93 × 10^-1/10^-7
T1/2 = 6.93× 10^(-1-(-7))
= 6.93 ×10^6s

DMI

1 year ago

yes that is correct

Landmarktutors

6 years ago

None of the options is correct. The answer is 6.93 x 10E6 s. Thanks

T-emma

11 years ago

no corr opt the ans should be 6.93*10¤

T-emma

11 years ago

no corr opt the ans should be 6.93*10¤6

madedayo

12 years ago

It should be 6.93*10^6

GoddyJR

6 years ago

there is no answer
6.93×10^6