An electron of charge 1.6 x 10-19C is accelerated between two metal plates. If the kinetics energy of the electron is 4.8 x 10-17J, the potential difference between the plate is
In general, if a charged particle is accelerated between two metal plates/a region by a potential difference V volts, the work done on the charge, given by the product of the charge and the potential difference, is equal to the kinetic energy of the charge
Thus eV = K.E
1.6 x 10\(^{-19}\) x V = 4.8 x 10\(^{-17}\)
∴ V = \(\frac{4.8 \times 10^{-17}}{1.6 \times 10^{-19}}\)
= 300V
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}