A wire of 5Ω resistance is drawn out so that its new length is two times the original length. If the resistivity of the wire remains the same and the cross-sectional area is halved, the new resistance is

little_missy

1 year ago

i got 5

Lucy_Teresa

1 year ago

5 doubled= 5*2=10
½*10
cross multiply
2*10/1 =20

DominicAfam

1 year ago

R1=5
R2=?😭
A2=1/2A1 that is A1=1, A2=1/2
L2=2L1 that is L1=1, L2=2

Formular
R=L/A

(R1=L1/A1)
(R2=L2/A2)

Key in those values above👆
(5=1/1)
(R2=2/[1/2]) or (R2=2/0.5)

We then have,
5=1
R2=4

Cross multiply
R2=5×4
R2=20😂

✌️

christa2026bel09

2 months ago

please is there any short form of this equation

praizlee100

1 year ago

40π is correct my school check again

realstixx

1 year ago

not clear