A positive charged rod X is brought near as uncharged metal sphere Y and is then touched by a finger with X still in place. When the finger is removed, the result is that y has
no charge and a zero potential
a positive charge and zero potential
a negative charge and positive potential
a negative charge and a negative potential
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Discussions (15)
๐๐ง๐๐ฎ๐๐ญ๐ข๐จ๐ง produces charges of opposite polarity i.e if the inducing charge is positive, the induced charge will be ๐๐๐ ๐๐ญ๐ข๐ฏ๐...A ๐๐จ๐ฌ๐ข๐ญ๐ข๐ฏ๐ ๐๐จ๐ญ๐๐ง๐ญ๐ข๐๐ฅ means that the charge of the influencial particle is ๐ญ๐ก๐ ๐ฌ๐๐ฆ๐ as the charge of the influenced particle. ๐๐ข๐ง๐๐ ๐ฅ๐ข๐ค๐ ๐๐ก๐๐ซ๐ ๐๐ฌ ๐ซ๐๐ฉ๐๐ฅ, ๐๐จ๐ซ๐ค ๐ก๐๐ฌ ๐ญ๐จ ๐๐ ๐๐จ๐ง๐ against the coulombic forces between the charges to bring them closer.
A ๐ง๐๐ ๐๐ญ๐ข๐ ๐ ๐ฉ๐จ๐ญ๐๐ง๐ญ๐ข๐๐ฅ means that the charge of the influential particle is the ๐จ๐ฉ๐ฉ๐จ๐ฌ๐ข๐ญ๐ of the influenced particle. ๐๐ข๐ง๐๐ ๐ฎ๐ง๐ฅ๐ข๐ค๐ ๐๐ก๐๐ซ๐ ๐๐ฌ ๐๐ญ๐ญ๐ซ๐๐๐ญ, they wouldn't need external work to bring them closer.
๐ข.๐ ๐๐๐ ๐๐ญ๐ข๐ฏ๐ ๐๐ก๐๐ซ๐ ๐ ๐๐จ๐๐ฒ ๐๐ง๐ ๐๐๐ ๐๐ญ๐ข๐ฏ๐ ๐ฉ๐จ๐ญ๐๐ง๐ญ๐ข๐๐ฅ...๐
The answer should be D. This is because the metal sphere acquires an opposite charge to the charge that brought near to it before earthing. It also has a negative potential. t
This can be seen in New School Physics. Chapter 5. Check Charging the Electoscope b. Alply the opposite to the steps and you get the answer
I too, think the answer is wrong. This is among the few answers that needs an official explanation.
The correct answer isn't **D** because of the relationship between charge and potential. Here's a breakdown:
1. **Charge and Potential**: When the positively charged rod is brought near the metal sphere, it induces a negative charge on the side of the sphere closer to the rod and a positive charge on the opposite side. When you touch the sphere with a finger, electrons from your body (ground) flow to the sphere to neutralize the positive charge. Once the finger is removed, the sphere is left with an excess of electrons, hence a negative charge.
2. **Potential**: The potential of the sphere is determined by the distribution of charges. The sphere itself is negatively charged after the process, but because it is still near the positively charged rod, the electric field from the rod influences the sphere, causing the sphere to have a positive potential overall.
If the sphere had a **negative potential**, it would mean that the sphere is isolated and no positive charge nearby is influencing it. But in this scenario, the sphere still has a positive potential because of the nearby positively charged rod.
**Answer D (a negative charge and a negative potential)** would be correct if the positively charged rod were removed before the finger was, allowing the sphere to retain a net negative charge and have a negative potential. But since the rod is still in place, the correct answer is **C: a negative charge and a positive potential**.
please chogozie which page in new school physics is this in, cos i have searched and i didn't see where they talked abt positive and negative potential
A positive rod near a neutral sphere induces charge separation: negative charges attract near the rod, positive charges repel to the far side.
Touching the sphere grounds it, allowing electrons from the Earth to be attracted by the positive rod and neutralize the repelled positive charges.
Removing the finger traps these excess electrons on the sphere, giving it a net negative charge.
With a net negative charge, the sphere now has a negative electric potential.
Removing the positive rod allows this negative charge to distribute evenly over the sphere's surface.
Therefore, the sphere ends up with a negative charge and a negative potential.
I believe the answer should be A.... Becuase the sphere actually conducted the charge, but the sphere was not on an insulator, so therefore the charge it conducted goes to the Earth , and it becomes neutral again .
