If 1.2 x 10^6J of heat energy is given off in 1 sec from a vessel maintained at a temperature gradient of 30Km-1, the surface area of the vessel is

[ thermal conductivity of the vessel = 400Wm-1K-1]

Obehs

6 years ago

how did you get 400 as thermal conductivity

Domnickado

3 years ago

I really gained a lot from this question 😊

BrownStanley2007

2 years ago

This is how it done
Heat transfer rate = temperature gradient*Thermal conductivity*Surface area

Though the thermal conductivity was omitted take it to be 400

Iheka

3 years ago

please how did you get 400

Toclay

5 years ago

I wonder

Ay0m1

1 year ago

The problem is that thermal conductivity is not included in other past questions and cbt apps
Thanks a lot Myschool for the insightful addition

Oguche_De

2 years ago

The heat capacity is not given.please can you change it.Thanks.