A 2000W electric heater is used to heat a metal object of mass 5kg initially at 10oC. If a temperature rise of 30oC is obtained after 10min, the heat capacity of the material is
6.0 x 104JoC-1
4.0 x 104JoC-1
1.2 x 104JoC-1
8.0 x 103JoC-1
Explanation
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Well guys many may think im wrong but the answer is B....... let me give my solution
IVT=CpΔθ
IV=2000W
T=10*60=600sec
θ1=10° C
then the twisting part in the question
Δθ= 30° C
It was stated that the "temperature rise" was 30° C which is completely different from "the final temperature after heating the metal"
Cp=?
IVT = CpΔθ
Cp=IVT/Δθ
Cp= 2000*600/30
Cp= 1,200,000/30
Cp= 40,000
Cp= 4.0 x 10^4JoC-1
option B is correct
Heat capacity =pt
———
Change in temperature
Pt = 2000*10*60
=1200000
Heat capacity = 1200000/(30-10)
=1200000/20
=6 * 10^4 therefore A
I thought C = mc
I.e Heat capacity = mass * specific heat capacity? Someone should please comment.
Mass m isn't included bcoz dey.ar.talkin abt Heat Capacity not Specific Heat Capacity
the formula applicable is PT = MCT
WHEN T IS CHANGE IN TEMPERATURE
2000 X 60 X 10 = 5 X C X (30-10)
C = 2000X600/100
C= 12000
ANS ....C
There already said temperature rise of 30 degree celcius so we need not subtract 10 from 30
I made that mistake
we were asked to find heat capacity but instead the answer shows specific heat capacity
I think the answer is A
10+273 =283
30+273 =303
303-283= 20
c = 2000 x 10 x 60
-----------------
20 x 5
= 12,000
c = 5 x 12,000
= 60,000.
