A turning fork of frequency 340Hz is vibrated just above a cylindrical tube of height 1.2m. If water is slowly poured into the tube, at what maximum height will resonance occur.
[speed of sound in air = 340ms-1]
0.95m
0.60m
0.50m
0.45m
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Discussions (26)
this answee is very wrong, i just dislike this my school.
when were asked to look for the minumum height then we'd end our calculation at the first resonance
but the question said maximum height, of course we can get, l=£/4, where l=0.25, then l=3£/4, where l=0.75. now this is the maximum height because, if we move further we'd get a lenght more than the one given which is 1.2. lets try it ( l=5£/4, here l=1.25...obviously, i hope you get now.) so the maximum height is the 2nd harmonics(3rd overtone)
but nah resonance sha.
please just know that its the question that was wrong, no be so i see am for all inclusive and even in jamb remix.
I strongly believe the answer should be A ie 0.95m because if you check well you'll see that they asked for maximum height of water, not maximum depth of the tube
Pls exolain you arrived at that answer and pls myschool should at least try to provide comprehensive answers and solution to questions
E = mc² Where: E is the energy released m is the mass defect (mass lost) C = 3.0 × 108 m/s (speed of light)
Step-by-step solution: Given: Total mass of material = 0.1, g = 0.1 × 10-3, kg = 1.0 × 10-4, kg Decrease in mass = 0.01% of 0.1 g m = 0.01 100 × 1.0 × 10-4 = 1.0 × 10-8 kg Now calculate the energy: E = mc² = 1.0 × 10-8 (3.0 × 108)². E = 1.0 × 10-8.9.0 × 1016 = 9.0 x 10⁸Joules
please why do you people stop at the 3rd resonance because we were not told of how many times
