The stylus of a phonograph record exerts a force of 7.7 x 10\(^{-2}\)N on a groove of radius 10\(^{-5}\)m. Compute the pressure exerted by the stylus on the groove
Pressure P = \(\frac{F}{A}\); Pressure P = \(\frac{F}{\pi r^2}\)
= \(\frac{7.7 \times 10^{-2}}{\pi \times 10^{-10}}\)
= 2.45 x 10\(10^8\)Nm\(^{-2}\)
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