At what frequency would a capacitor of 2.5μF used in the radio circuit have a reactance of 250Ω
X\(_c\) = \(\frac{1}{2\pi f c}\)
f = \(\frac{1}{ 2 \pi f C}\) = \(\frac{1}{\pi \times 2 \times 250 \times 2.5 \times 10^{-6}}\)
f = \(\frac{1\times 10^6}{ 1250 \pi}\)
f = \(\frac{800}{π}\)
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