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 \(^{23}_{11}\)Na + X  → \(^{20}_9\)F + \(^4_2\)He What particle is X in the reaction above?

Physics
JAMB 2002

 \(^{23}_{11}\)Na + X  → \(^{20}_9\)F + \(^4_2\)He

What particle is X in the reaction above?

  • A. Alpha
  • B. Beta
  • C. Neurons
  • D. Gamma
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Correct Answer: Option C
Explanation

The particle in the reaction is a neutron

 \(^{23}_{11}\)Na + \(^1_0\)n  → \(^{20}_9\)F + \(^4_2\)He

 


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