\(^{23}_{11}\)Na + X → \(^{20}_9\)F + \(^4_2\)He
What particle is X in the reaction above?
The particle in the reaction is a neutron
\(^{23}_{11}\)Na + \(^1_0\)n → \(^{20}_9\)F + \(^4_2\)He
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