\(^{23}_{11}\)Na + X  → \(^{20}_9\)F + \(^4_2\)He

What particle is X in the reaction above?

Dave333

4 years ago

Note: it's not beta because,it is not -1
So,23+X=20+4
X=24-23=1
Now,11+X=9+2
X=11-11=0
😊

wqkeelah

1 year ago

The presence of Helium alone shows that is a option A

BIG S

1 year ago

the diagram is not even showing

nwabuezedaniel01

2 months ago

the answer is beta not neutron