an electric cell with nominal voltage E has a resistance of 3Ω connected across it. If the voltage falls to 0.6E, the internal resistance of the cell is
a
1Ω
b
2Ω
c
3Ω
d
4Ω
Explanation
Correct Option
b
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Discussions (24)
olyezema
4 years ago
V=IR
0.6=3I
0.6/3=I
0.2A=I
Lost voltage [v]=1-0.6=0.4
v=Ir
0.4=0.2r
0.4/0.2=r
r=2Ω
olyezema
4 years ago
V=IR
0.6=3I
0.6/3=I
0.2A=I
Lost voltage [v]=1-0.6=0.4
v=Ir
0.4=0.2r
0.4/0.2=r
r=2Ω
azekah
1 year ago
firstly calculate your current v=ir
where v=0.6 r=0.3
0.6/0.3=0.2 that's ur I current oya calculate ur internal resistance
I= E/R+r 0.2=0.6/3+r
cross multiply
0.6+0.2r=0.6
collect like terms
0.2r=0.4
divide by 0.2
the final ans =2
