Correct Answer: Option A

Explanation

The energy store is equal to the work done in stretching the wire from E to F given by the \(\frac{1}{2}\)Fe

where e = 0.10 - 0.50 = 0.05m.

F = 0.2 + 0.1 = 0.3N

= \(\frac{1}{2}\) x (0.2 + 0.1) x (0.10 - 0.50) = 7.5 x 10\(^{-3}\)J

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