If ray travelling in air is incident on a transparent medium as shown in the diagram, the refractive index of the medium is given as

cosα / sinβ
sinα / sinβ
cosβ / sinα
sinβ / sinα
Explanation

Video Explanation
Post your Contribution
Discussions (7)

From Snell's second law of refraction, the refractive index of a medium is given as sine I/sine r

I disagree it's meant to be B that's the correct answer and Snell's law states the refractive index as sin I/sin r. where I is the incident angle which is a and r is the refracted angle which is b

The answer is correct. The angle of incidence is usually measured to the normal, not the surface. Therefore, i = sin (90-@). In trigonometry, sin (90-@) = cos @. Therfore, applying snell's law, refractive index, n = cos @ / sin B
** I used @ to represent alpha and B to represent beta

