The velocity y of a particle in a time t is given by the equation
y = 10 + 2t\(^2\)
Find the instantaneous acceleration after 5 seconds

ICEDOK

3 years ago

a = v - u/t
a = v/t
and v = 10 + 2t²
Substitute for v
a = 10 + 2t² / t
a = 10 + 2t
Instantaneous acceleration after 5 seconds
t=5
a = 10 + 2(5)
a = 10 + 10
a = 20m/s

kencoli

3 years ago

i don't understand this

s.samuel

2 years ago

People that didn't do maths won't understand this question

OseNoah0007

3 years ago

There's differentiation here.....finding the first derivative of v..... that's why it's 4t.... cause differentiation of 10 is 0 then of 2t² is 4t...

Mr_Philsual

3 years ago

If V=10 + 2t^2

Acceleration, a = v-u/t
a= dv/dt

And V=10 + 2t^2
Then, 0 × 10^0-1 + 2 × 2t^2-1
=o + 4t
t=5s.
a=4 × 5
= 20ms-2

Legacy61

2 months ago

whytine ss talk nah true sha ppl wey no sabi differentiation go think say the answer is wrong 😉😏😁

Usmanmuhammed2009001

1 year ago

I don't understand please explain better