In the circuit above, The potential across each capacitor is 100V. The total energy stored in the two capacitors is
Energy stored in a capacitor is given by
E = \(\frac{1}{2}\)CV\(^2\)
But the effective capacitance for the parallel arrangement is given by
C = C\(_1\) + C\(_2\)
= 2 + 3
= 5μF = 5 x 10\(^{-6}\) x (100)\(^2\)
∴E = \(\frac{1}{2}\)CV\(^2\)
= \(\frac{1}{2}\) x 5 x 10\(^{-6}\) x 10\(^4\)
2.9 x 10\(^{-2}\)J
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}