The diagram above shows the velocity-time graph of a vehicle. Its acceleration and retardation respectively are

8.0 ms-2, 4,0 ms-2
4.0 ms-2, 8.0 ms-2
4.0 ms-2, 2.0 ms-2
2.0 ms-2, 4.0 ms-2
Explanation

Video Explanation
No video available
Post your Contribution
Discussions (8)

To find the acceleration
a=V-U/t
a=80-0/20
a=4ms-2
To find the retardation
a= U-V/t
a=80-0/40
a=2ms-2

To determine the acceleration and retardation of the vehicle, we need to analyze the velocity-time graph.
Acceleration is the rate of change of velocity. In the graph:
- The initial velocity is 0 m/s, and the final velocity is 40 m/s.
- The time taken to reach the final velocity is 10 seconds.
The acceleration (a) can be calculated as:
a = Δv / Δt
= (40 m/s - 0 m/s) / 10 s
= 4.0 m/s²
Retardation is the rate of decrease of velocity. In the graph:
- The initial velocity is 40 m/s, and the final velocity is 0 m/s.
- The time taken to reach the final velocity is 5 seconds.
The retardation (r) can be calculated as:
r = Δv / Δt
= (0 m/s - 40 m/s) / 5 s
= -8.0 m/s²
Since retardation is a deceleration, it's negative, but we're interested in its magnitude. Therefore:
- Acceleration = 4.0 m/s²
- Retardation = 8.0 m/s²
The correct answer is B: 4.0 ms⁻², 8.0 ms⁻².

Actually, wit d cross checking I've done, ℓ̊ believe ℓ̊ shld ave scored abt 230 with abt 9 wrng questnz sum of which ℓ̊ commented on n ℓ̊ didn't on sum...

