Correct Answer: Option A

Explanation

\(\left(\frac{81}{16}\right)^{\frac{-1}{4}}\times 2^{-1}\)  =  \(\frac{1}{\left(\frac{81}{16}\right)^{\frac{1}{4}}}\times \frac{1}{2}\)
= \(\left(\frac{16}{81}\right)^{\frac{1}{4}}\times \frac{1}{2}\)
= \(\left(\frac{2}{3}\right)^{4\times \frac{1}{4}}\)
=\(\frac{2}{3}\times \frac{1}{2}\)
= \(\frac{1}{3}\)

There is an explanation video available below.

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