In how many ways can a delegation of 3 be chosen from 5 men and 3 women. If at least 1 man and 1 woman must be included?
= \((^{5}C_{2} \times ^{3}C_{1}) + (^{5}C_{1} \times ^{3}C_{2})\)
= \((10 \times 3) + (5 \times 3)\)
= 45.
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