If the hypotenuse of a right-angled isosceles triangle is 2cm. What is the area of the triangle?
X\(^2\) + x\(^2\) = 2\(^2\)
2x\(^2\) = 4
x\(^2\) = 4/2
x\(^2\) = 2
x = +/-√2
Area of Δ = 1/2bh
= 1/2 x √2 x √2
= 2/2
= 1 cm\(^2\)
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