Correct Answer: Option C

Explanation

\(\int^{\frac{\pi}{2}} _{\frac{-\pi}{2}} cos x dx = [sinx]^{\frac{\pi}{2}} _{\frac{-\pi}{2}}\)
=sin\(\frac{\pi}{2} - sin\frac{-\pi}{2}\)
= sin90 – sin(-90)
= sin90 – sin270
= 1 – (-1)
= 1+1
= 2

There is an explanation video available below.

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