Differentiate sin x - x cos x

a

x cos x

b

x sin x

c

-x cos x

d

-x sin x

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Correct Option
b

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panderson
1 year ago
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So Its Me Anonymous time for me to solve this:
We need to differentiate: 𝑦 = sin π‘₯ βˆ’ π‘₯cosπ‘₯
Step 1: Differentiate Term by Term

Using the derivative rules:
Derivative of sinπ‘₯:
𝑑y/𝑑π‘₯(sin⁑π‘₯)=cos⁑π‘₯
Derivative of π‘₯cos⁑π‘₯ (Product Rule): The product rule states:
𝑑y/𝑑π‘₯[𝑒𝑣]=𝑒′𝑣+𝑒𝑣′
Let 𝑒 = π‘₯ and 𝑣 = cosπ‘₯,
then: 𝑒′ = 𝑑y/𝑑π‘₯ π‘₯=1
𝑣′ = 𝑑y/𝑑π‘₯ cosπ‘₯ = βˆ’sinπ‘₯
Applying the product rule:
𝑑y/𝑑π‘₯(π‘₯cos⁑π‘₯)=(1)(cos⁑π‘₯)+(π‘₯)(βˆ’sinπ‘₯) = cosπ‘₯ βˆ’ π‘₯sinπ‘₯
Step 2: Put Everything Together
𝑑𝑦𝑑π‘₯=cos⁑π‘₯βˆ’(cos⁑π‘₯βˆ’π‘₯sin⁑π‘₯)
Distribute the negative sign:
𝑑𝑦𝑑π‘₯ = cos⁑π‘₯ βˆ’ cosπ‘₯ + π‘₯sinπ‘₯
​
Final Answer:
𝑑𝑦𝑑π‘₯=π‘₯sinπ‘₯βœ…

Leinad321
2 years ago

sinx when differentiated gives cosx
gor xcos x
let u=x and v=cos x
du/dx=1 dv/dx=-sinx (differentiating individually first)

using the product rule i.e
dy/dx=du/dx Γ—V +dv/dx Γ—U
dy/dx=1Γ—cos x+(-sinx Γ— x)
dy/dx=cosx-xsinx
put back in equation
cosx-(cosx-xsinx)
cosx-cosx+xsinx
=xsinx

runaboy
1 year ago

i don't understand

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