If p varies inversely as the square of q and p=8 when q=4, find q when p =32
p ∝ 1/q p = k/q K = q\(^2\)p = 4\(^2\)(8) ∴p = 128/q 32 = 128/q q\(^2\) = 128/32 q\(^2\) = 4 q = √4 = \(\pm\) 2
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